An object with a mass of $2 k g$ $2 kg$ is traveling in a circular path of a radius of $4 m$ $4 m$ . If the object's angular velocity changes from $1 H z$ $1 Hz$ to $19 H z$ $19 Hz$ in $3 s$ $3 s$ , what torque was applied to the object?

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Answer 1 · 2017-01-15T09:12:40

The torque is $= 1206.4 N m$ $=1206.4Nm$

The torque is the rate of change of angular momentum

$τ = \frac{d L}{d t} = \frac{d (I ω)}{d t} = I \frac{d ω}{d t}$ $tau=(dL)/dt=(d(Iomega))/dt=I(domega)/dt$

The moment of inertia of the object is $I = m r^{2}$ $I=mr^2$

$= 2 \cdot 4^{2} = 32 k g m^{2}$ $=2*4^2= 32 kgm^2$

The rate of change of angular velocity is

$\frac{d ω}{d t} = \frac{19 - 1}{3} \cdot 2 π$ $(domega)/dt=(19-1)/3*2pi$

$= (12 π) r a d s^{- 2}$ $=(12pi) rads^(-2)$

So the torque is $τ = 32 \cdot 12 π N m = 384 π N m = 1206.4 N m$ $tau=32*12pi Nm=384piNm=1206.4Nm$

An object with a mass of 2kg 2 kg is traveling in a circular path of a radius of 4m4 m. If the object's angular velocity changes from 1Hz 1 Hz to 19Hz 19 Hz in 3s 3 s, what torque was applied to the object?