An object with a mass of $2 kg$ is traveling in a circular path of a radius of $2 m$ . If the object's angular velocity changes from $2 Hz$ to $4 Hz$ in $1 s$ , what torque was applied to the object?

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Answer 1 · 2017-10-25T06:32:36

The torque is $=100.5Nm$

The torque is the rate of change of angular momentum

$tau=(dL)/dt=(d(Iomega))/dt=I(domega)/dt$

The mass of the object is $m=2kg$

The radius is $r=2m$

For the object, $I=mr^2$

So, $I=2*(2)^2=8kgm^2$

And the rate of change of angular velocity is

$(d omega)/dt=(Deltaomega)/t=(8pi-4pi)/1=(4pi)rads^-2$

So,

The torque is

$tau=8*4pi=100.5Nm$

An object with a mass of 2 kg 2 kg is traveling in a circular path of a radius of 2 m2 m. If the object's angular velocity changes from 2 Hz 2 Hz to 4 Hz 4 Hz in 1 s 1 s, what torque was applied to the object?