An object with a mass of #2 kg# is revolving around a point at a distance of #5 m#. If the object is making revolutions at a frequency of #1 Hz#, what is the centripetal force acting on the object?

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Answer 1 · 2017-10-01T15:58:40

#40pi^2#

Centripetal force is given by #F=(m*v^2)/r#

where ,

m is the mass of the particle ,
v is the velocity of the particle,
and r is the radius of the circle of revolution.

Here frequency ( #nu#) is given as #1HZ#

#v=romega#
#omega# is the angular velocity of the particle and is equal to #2pinu#

Therefore
#omega=2pi*1#
#v=r*2pi#
#v=10pi#

#F=(2*(10pi)^2)/5#

#F=(200*pi^2)/5#
#F=40pi^2# is the centripetal force acting on the particle