An object with a mass of $2 k g$ $2 kg$ is hanging from an axle with a radius of $3 m$ $3 m$ . If the wheel attached to the axle has a radius of $3 m$ $3 m$ , how much force must be applied to the wheel to keep the object from falling?

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Answer 1 · 2017-06-25T15:23:34

The force is $= 19.6 N$ $=19.6N$

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The load $L = (2 g) N$ $L=(2g)N$

Radius of axle $r = 3 m$ $r=3m$

Radius of wheel $R = 3 m$ $R=3m$

Taking moments about the center of the axle

$F \cdot R = L \cdot r$ $F*R=L*r$

$F \cdot 3 = 2 \cdot g \cdot 3$ $F*3=2*g*3$

$F = \frac{2 \cdot g \cdot 3}{3} = 2 g = 19.6 N$ $F=(2*g*3)/3=2g=19.6N$

The force is $F = 19.6 N$ $F=19.6N$

We expect this value as the radius of the axle is equal to the radius of the wheel,

$r = R$ $r=R$

An object with a mass of 2kg2 kg is hanging from an axle with a radius of 3m3 m. If the wheel attached to the axle has a radius of 3m3 m, how much force must be applied to the wheel to keep the object from falling?