An object with a mass of $2 k g$ $2 kg$ is hanging from an axle with a radius of $3 m$ $3 m$ . If the wheel attached to the axle has a radius of $2 m$ $2 m$ , how much force must be applied to the wheel to keep the object from falling?

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Answer 1 · 2018-02-02T15:01:42

The force is $F = 29.4 N$ $F=29.4N$

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The load is $L = 2 g N$ $L=2gN$

The radius of the axle is $r = 3 m$ $r=3m$

The radius of the wheel is $R = 2 m$ $R=2m$

The effort is $= F N$ $=FN$

The acceleration due to gravity is $g = 9.8 m s^{- 2}$ $g=9.8ms^-2$

Taking moments about the center of the axle

$F \cdot 2 = 2 g \cdot 3$ $F*2=2g*3$

$F = \frac{2 g \cdot 3}{2} = 29.4 N$ $F=(2g*3)/2=29.4N$

The force is $F = 29.4 N$ $F=29.4N$

An object with a mass of 2kg2 kg is hanging from an axle with a radius of 3m3 m. If the wheel attached to the axle has a radius of 2m2 m, how much force must be applied to the wheel to keep the object from falling?