An object with a mass of 160 g is dropped into 880 mL of water at 0^@C. If the object cools by 120 ^@C and the water warms by 5 ^@C, what is the specific heat of the material that the object is made of?

1 Answer
Sihan Tawsik
Feb 3, 2016

1004.35jkg^(-1)K^(-1)

Explanation:

suppose,
the specific heat of the object is S
now,
we know,
1ml water= 1gm
:.880ml water=880gm
=0.88kg
and we know,
heat loss= heat gain
0.16Sxx(120-5)=0.88xx4200xx5
=>18.4S=18480
=>S=1004.35jkg^(-1)K^(-1)

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