An object with a mass of $150 g$ $150 g$ is dropped into $500 m L$ $500 mL$ of water at $0^{\circ} C$ $0^@C$ . If the object cools by $60^{\circ} C$ $60 ^@C$ and the water warms by $9^{\circ} C$ $9 ^@C$ , what is the specific heat of the material that the object is made of?

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Answer 1 · 2016-09-14T19:17:39

$2095 J / k g . K$ $2095J//kg.K$

Conservation of energy : Energy lost by object equals energy gained by water.

$therefore (mc Delta T)_ (object) = (mcDeltaT)_(water)$

$therefore (0.150)(c)(60)=(0.500)(4190)(9)$

$therefore c_(object) = 2095J//kg.K$

An object with a mass of 150 g150g150 g is dropped into 500 mL500mL500 mL of water at 0^@C0∘C0^@C. If the object cools by 60 ^@C60∘C60 ^@C and the water warms by 9 ^@C9∘C9 ^@C, what is the specific heat of the material that the object is made of?