An object with a mass of $120 g$ is dropped into $800 mL$ of water at $0^@C$ . If the object cools by $24 ^@C$ and the water warms by $3 ^@C$ , what is the specific heat of the material that the object is made of?

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An object with a mass of $120 g$ is dropped into $800 mL$ of water at $0^@C$ . If the object cools by $24 ^@C$ and the water warms by $3 ^@C$ , what is the specific heat of the material that the object is made of?

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Answer 1 · 2016-02-07T18:16:40

$c_m=0,0008bar3$

Explanation:

$"800 m L of water"=800 mg=0,8 g$
$Q_w=m_w *c_w * Delta t_w " Heat gained by water"$
$Q_w=0,8*1*3=2,4 Cal$
$Q_m=m_m*c_m*Delta t_m" Heat given by mass"$
$Q_m=120*c_m*24$
$Q_m=2880*c_m$
$Q_m=Q_w$
$2880*c_m=2,4$
$c_m=(2,4)/2880$
$c_m=0,0008bar3$

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An object with a mass of $120 g$ is dropped into $800 mL$ of water at $0^@C$ . If the object cools by $24 ^@C$ and the water warms by $3 ^@C$ , what is the specific heat of the material that the object is made of?

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An object with a mass of 120 g120 g is dropped into 800 mL800 mL of water at 0^@C0^@C. If the object cools by 24 ^@C24 ^@C and the water warms by 3 ^@C3 ^@C, what is the specific heat of the material that the object is made of?

1 Answer

Explanation:

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An object with a mass of $120 g$ is dropped into $800 mL$ of water at $0^@C$ . If the object cools by $24 ^@C$ and the water warms by $3 ^@C$ , what is the specific heat of the material that the object is made of?