An object with a mass of $12 k g$ $12 kg$ , temperature of $210^{o} C$ $210 ^oC$ , and a specific heat of $7 \frac{J}{k g \cdot K}$ $7 J/(kg*K)$ is dropped into a container with $32 L$ $32 L$ of water at $0^{o} C$ $0^oC$ . Does the water evaporate? If not, by how much does the water's temperature change?

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Answer 1 · 2017-07-18T05:57:48

$DeltaT=208.8^circC$ The water will evaporate.

$210^circC~~483K$
$0^circC~~273K$
$32L=0.032m^3~=0.032kg$

$m_oC_oDeltaT_o=m_wC_wDeltaT_w$

$12*7*(483-T)=0.032*4.18*(273+T)$

#40572-84T=36.51648+0.13376T

$84.13376T=40535.4835$

$T=40535.4835/84.13376=481.798074K=208.798074^circC~~208.8^circC$

$0+208.8=208.8^circC$

As $208.8gt100$ the water will evaporate.

An object with a mass of 12 kg12kg12 kg, temperature of 210 ^oC210oC210 ^oC, and a specific heat of 7 J/(kg*K)7Jkg⋅K7 J/(kg*K) is dropped into a container with 32 L 32L32 L of water at 0^oC 0oC0^oC . Does the water evaporate? If not, by how much does the water's temperature change?