An object with a mass of $100 g$ is dropped into $500 mL$ of water at $0^@C$ . If the object cools by $20 ^@C$ and the water warms by $4 ^@C$ , what is the specific heat of the material that the object is made of?

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An object with a mass of $100 g$ is dropped into $500 mL$ of water at $0^@C$ . If the object cools by $20 ^@C$ and the water warms by $4 ^@C$ , what is the specific heat of the material that the object is made of?

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Answer 1 · 2017-07-28T05:59:31

Specific heat of the object is $1$

Explanation:

In such cases, heat lost is equal to heat gained. Further heat lost / gained is given by $mst$ , where $m$ is the mass of the object, $s$ is its specific heat and $t$ is rise / fall in temperature.

Hence let $s$ be the specific heat of the object, then heat lost by the object is $100xxsxx20=2000s$ calories

annd heat gained by water is $500xx1xx4=2000$ calories.

Hence $2000s=2000$ or $s=1$

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An object with a mass of $100 g$ is dropped into $500 mL$ of water at $0^@C$ . If the object cools by $20 ^@C$ and the water warms by $4 ^@C$ , what is the specific heat of the material that the object is made of?

1 Answer

Explanation:

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Humanities

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An object with a mass of 100 g100 g is dropped into 500 mL500 mL of water at 0^@C0^@C. If the object cools by 20 ^@C20 ^@C and the water warms by 4 ^@C4 ^@C, what is the specific heat of the material that the object is made of?

1 Answer

Explanation:

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An object with a mass of $100 g$ is dropped into $500 mL$ of water at $0^@C$ . If the object cools by $20 ^@C$ and the water warms by $4 ^@C$ , what is the specific heat of the material that the object is made of?