An object with a mass of $100 g$ is dropped into $500 mL$ of water at $0^@C$ . If the object cools by $50 ^@C$ and the water warms by $4 ^@C$ , what is the specific heat of the material that the object is made of?

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Answer 1 · 2017-03-04T14:34:59

The specific heat is $=1.67kJkg^-1K^-1$

The heat transferred from the hot object, is equal to the heat absorbed by the cold water.

For the cold water, $Delta T_w=4º$

For the metal $DeltaT_o=50º$

$m_o C_o (DeltaT_o) = m_w C_w (DeltaT_w)$

$C_w=4.186kJkg^-1K^-1$

$m_0 C_o*50 = m_w* 4.186 *4$

$0.1*C_o*50=0.5*4.186*4$

$C_o=(0.5*4.186*4)/(0.1*50)$

$=1.67kJkg^-1K^-1$

An object with a mass of 100 g100 g is dropped into 500 mL500 mL of water at 0^@C0^@C. If the object cools by 50 ^@C50 ^@C and the water warms by 4 ^@C4 ^@C, what is the specific heat of the material that the object is made of?