An object with a mass of $10 g$ is dropped into $120 mL$ of water at $0^@C$ . If the object cools by $60 ^@C$ and the water warms by $5 ^@C$ , what is the specific heat of the material that the object is made of?

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An object with a mass of $10 g$ is dropped into $120 mL$ of water at $0^@C$ . If the object cools by $60 ^@C$ and the water warms by $5 ^@C$ , what is the specific heat of the material that the object is made of?

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Answer 1 · 2016-03-05T11:58:30

$c_o=1 " "(Cal)/(gr*^o C)" made of water"$

Explanation:

$Q_o=m_o*c_o*Delta t_o" Heat given by Object"$
$Q_o=10*c_o*60=600*c_o$
$Q_w=m_w*c_w*Delta t_w" Heat gained by water"$
$120" " m L" of water:120 gr"$
$c_w=1 (Cal)/(gr*^o C)$
$Q_w=120*1*5=600$
$W_o=Q_w$
$600*c_o=600$
$c_o=1 " "(Cal)/(gr*^o C)" made of water"$

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An object with a mass of $10 g$ is dropped into $120 mL$ of water at $0^@C$ . If the object cools by $60 ^@C$ and the water warms by $5 ^@C$ , what is the specific heat of the material that the object is made of?

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An object with a mass of 10 g10 g is dropped into 120 mL120 mL of water at 0^@C0^@C. If the object cools by 60 ^@C60 ^@C and the water warms by 5 ^@C5 ^@C, what is the specific heat of the material that the object is made of?

1 Answer

Explanation:

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An object with a mass of $10 g$ is dropped into $120 mL$ of water at $0^@C$ . If the object cools by $60 ^@C$ and the water warms by $5 ^@C$ , what is the specific heat of the material that the object is made of?