An object with a mass of #1 kg# is lying still on a surface and is compressing a horizontal spring by #1/3 m#. If the spring's constant is #3 (kg)/s^2#, what is the minimum value of the surface's coefficient of static friction?

Question

1149 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-12-02T07:02:08

The coefficient of static friction is #=0.1#

The force of friction is

#F_r=k*Deltax#

The spring constant is #k=3kgs^-2#

The compression of the spring is #Deltax=1/3m#

Therefore,

#F_r=3*1/3=1N#

The coefficient of static friction is

#mu_s=F_r/N#

The normal force is #N=mg=(1g) N#

The acceleration due to gravity is #g=9.8ms^-2#

So,

The coefficient of static friction is

#mu_s=(1)/(1g)=0.1#