An object travels North at 7 m/s for 5 s and then travels South at 9 m/s for 2 s. What are the object's average speed and velocity?

1 Answer
May 13, 2016

vecV_"net"=2.43m/s->"towards north"

V_"avg" ~~7.6m/s

Explanation:

For 1st 5s the velocity of the object towards North be
vecV_"north"=7hatjm/s

For 1st 5s the displacement of the object towards North be
vecd_"north"=7hatjm/sxx5s=35hatjm

For 2nd 2s the velocity of the object towards Southbe vecV_"south"=-9hatjm/s

For 2nd 2s the displacement of the object towards Southbe vecd_"south"=-9hatjm/sxx2s=-18hatjm

Net displacement during t=(5+2)=7s is
vecd_"net"=35hatjm-18hatjm=17hatjm->"towards north"

Hence the Net Velocity
vecV_"net"=vecd_"net"/t=17/7hatjm=2.43m/s->"towards north"

Total distance covered during 7 s
d_"total"=|vecd_"north"|+|vecd_"south"|=|35hatjm|+|-18hatjm|=53m

Hence Average speed
V_"avg" = d_"total"/t=53/7m/s~~7.6m/s