An object travels North at $2 m/s$ for $6 s$ and then travels South at $7 m/s$ for $4 s$ . What are the object's average speed and velocity?

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Answer 1 · 2018-02-23T15:43:10

Clearly,distance covered by the object in total $10 s$ is $6*2 + 7*4=40 m$

So,average speed = total distance covered/total time taken = $40/10 =4 ms^-1$

Again, net displacement is $(6*2 - 7*4)=-16 m$

So,average velocity = net displacement/total time taken = $-16/10=-1.6 ms^-1$

Negative sign indicates,direction of average velocity is towards south

An object travels North at 2 m/s 2 m/s for 6 s6 s and then travels South at 7 m/s 7 m/s for 4 s 4 s. What are the object's average speed and velocity?