An object is moving at a velocity or 8.8 m/s. It accelerates to a velocity of 35 m/s over a time of 6.3 s. What acceleration did it experience?

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Answer 1 · 2015-11-02T12:01:39

The acceleration is $"4.2 m/s"^2"$ .

Acceleration is the change in velocity over a periodic of time.

$a=(v_f-v_i)/(Deltat)$ , where $a$ is acceleration, $v_f$ is final velocity, $v_i$ is initial velocity, and $Deltat$ is time interval.

Known
$v_f=35"m/s"$
$v_i=8.8"m/s"$
$Delta t=6.3"s"$

Unknown
$a$

Equation

$a=(v_f-v_i)/(Deltat)$

Solution

$a=(35"m/s"-8.8"m/s")/(6.3"s")=$

$a=(26.2"m/s")/(6.3"s")="4.2 m/s/s=4.2 m/s"^2"$