An object has a mass of $6 kg$ . The object's kinetic energy uniformly changes from $120 KJ$ to $36 KJ$ over $t in [0, 4 s]$ . What is the average speed of the object?

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An object has a mass of $6 kg$ . The object's kinetic energy uniformly changes from $120 KJ$ to $36 KJ$ over $t in [0, 4 s]$ . What is the average speed of the object?

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Answer 1 · 2016-05-18T21:13:06

$bar v =159.178$

Explanation:

Calling $t_1=0, t_2= 4,E_1=120000,E_2=36000,m=6$
interpolating the kinetic energy $e$ we get
$e = E_1+((E_2-E_1)/(t_2-t_1))(t-t_1)$ but $e = 1/2mv^2$
also
$v = sqrt(2e/m)$ . Average speed is obtained calculating
$bar v =( int_{t_1}^{t_2}v dt)/(t_2-t_1) = 159.178$

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An object has a mass of $6 kg$ . The object's kinetic energy uniformly changes from $120 KJ$ to $36 KJ$ over $t in [0, 4 s]$ . What is the average speed of the object?

1 Answer

Explanation:

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Math

Humanities

... and beyond

An object has a mass of 6 kg6 kg. The object's kinetic energy uniformly changes from 120 KJ120 KJ to 36 KJ 36 KJ over t in [0, 4 s]t in [0, 4 s]. What is the average speed of the object?

1 Answer

Explanation:

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An object has a mass of $6 kg$ . The object's kinetic energy uniformly changes from $120 KJ$ to $36 KJ$ over $t in [0, 4 s]$ . What is the average speed of the object?