An elevator car weighs 5500 N. If the car accelerates upwards at a rate of 4.0 m/s2, what is the tension in the support cable lifting the car?

Question

Thanks for helping.

11031 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-18T00:04:30

$"The tension in the support cable is 7755 Newtons."$

enter image source here

$G:"represents weight of elevator(the red vector)"$
$F:"Force by inertia(the blue vector)"$
$T:"Tension in the cable"$

$T=F+G$

$T=m*a+G$

$m:"represents mass of elevator"$
$G=m*g$

$5500=m*g$

$m=5500/(9.81)$

$T=5500/(9.81)*4+5500$

$T=5500(4/(9.81)+1)$

$T=5500(0.41+1)$

$T=5500*1.41$

$T=7755" "N$