Aluminum will react with sulfuric acid in the following reaction: 2Al(s) + 3H_2SO_4(l) -> Al_2(SO_4)_3(aq) + 3H_2(g). How many moles of H_2SO_4 will react with 18 mol Al? How many moles of each product will be produced?

1 Answer
Jarni Renz
Jan 4, 2018

=27molH_2SO_4

Explanation:

With reference to the given balanced equation for the mole ratios, the needed number of moles for each remaining compound involved in the reaction using the mass of Al as basis for the molar conversions can be computed as;

etaH_2SO_4:
=18cancel(molAl)xx(3molH_2SO_4)/(2cancel(molAl))
=27molH_2SO_4

etaAl_2(SO_4)_3:
=18cancel(molAl)xx(1molAl_2(SO_4)_3)/(2cancel(molAl))
=9molAl_2(SO_4)_3

etaH_2:
=18cancel(molAl)xx(3molH_2)/(2cancel(molAl))
=27molH_2

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