What is the pH of a #"0.065 M"# aqueous solution of acetic acid? #K_a = 1.8 xx 10^(-5)#, and acetic acid, #"CH"_3"COOH"#, reacts with water as shown below: #"CH"_3"COOH"(aq) + "H"_2"O"(l) rightleftharpoons "CH"_3"COO"^(-)(aq) + "H"_3"O"^(+)(aq)#
1 Answer
Explanation:
As with all these problems, we first write out the equilibrium equation to inform our reasoning...
Now
Now INITIALLY,
And so we rewrite the equilibrium expression...
...and thus
We ASSUME that
Since the approximations have converged I am prepared to accept this value...this method of successive approximations is usually more efficient than pfaffing about with the quadratic equation...
And since