There are 5+3 valence electrons for which to account; and this gives 4 electron pairs arranged the central phosphorus atom. These assume a tetrahedral geometry, however, one of the arms of the tetrahedron is a lone pair, and geometry descends to trigonal pyramidal with respect to phosphorus.
The ∠H−P−H ≅ 94∘, whereas that for ∠H−N−H≅105∘. This difference in bond angles between the homologues is not readily rationalized, and beyond the scope of even a third year inorganic chemist. This bond angle discrepancy is also observed for H2S versus H2O.
So, the shape is PYRAMIDAL :

Hope it Helps :)