According to the equations below, what is the conjugate base of $HCO_3^-$ ?

Question

$H_2CO_3(aq) + H_2O (l) rightleftharpoons HCO_3^(-) (aq) + H_3O^(+)(aq)$

$HCO_3^(-)(aq) + H_2O(l) rightleftharpoons CO_3^(2-)(aq) + H_3O^(+)(aq)$

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Answer 1 · 2016-12-09T06:16:17

The conjugate base of $HCO_3^-$ is $CO_3^(2-)$

To find the conjugate base of ANY acid, all you have to do is remove a proton, and conserve mass and charge; simply take $H^+$ away.

e.g. $H_2SO_4 rarrHSO_4^-$

$HNO_3 rarrNO_3^-$

$H_3PO_4 rarr H_2PO_4^-$

$NH_3 rarr NH_2^-$

What is the conjugate acid of $CO_3^(2-)$ ion?

It seems I have asnwered this [before.](https://socratic.org/questions/how-do-you-determine-conjugate-acid-base-pairs)