According to the equations below, what is the conjugate base of #HCO_3^-# ?

Question

#H_2CO_3(aq) + H_2O (l) rightleftharpoons HCO_3^(-) (aq) + H_3O^(+)(aq)#

#HCO_3^(-)(aq) + H_2O(l) rightleftharpoons CO_3^(2-)(aq) + H_3O^(+)(aq)#

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Answer 1 · 2016-12-09T06:16:17

The conjugate base of #HCO_3^-# is #CO_3^(2-)#

To find the conjugate base of ANY acid, all you have to do is remove a proton, and conserve mass and charge; simply take #H^+# away.

e.g. #H_2SO_4 rarrHSO_4^-#

#HNO_3 rarrNO_3^-#

#H_3PO_4 rarr H_2PO_4^-#

#NH_3 rarr NH_2^-#

What is the conjugate acid of #CO_3^(2-)# ion?

It seems I have asnwered this before.