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ABC is a triangle whose sides AB = 6 cm, BC = 8 cm and AC = 12 cms. D is such a point situated on AC that angle ADB = angle ABC. Find the length of BD ?

1 Answer

Jan 7, 2017

drawn

In $Delta ABD and Delta ABC$

$/_BAD=/_BAC ("common")$
$/_ADB=/_ABC ("given")$
$/_ABD=/_ACB ("remaining")$

So $Delta ABD and Delta ABC$ are SIMILAR

Hence

$(BD)/(BC)=(AB)/(AC)$

$BD=(ABxxBC)/(AC)=(6xx8)/12=4cm$

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