A wheel has angular acceleration of 3 rad/sec² and an initial angular speed of 2 rad/sec. In a time of 2sec it has rotated through an angle of (in radians)?

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Answer 1 · 2018-01-13T10:29:01

The angle is $= 10 r a d$ $=10rad$

The angular acceleration is $α = 3 r a d s^{- 2}$ $alpha=3rads^-2$

The initial angular speed is $ω_{0} = 2 r a d s^{- 1}$ $omega_0=2rads^-1$

The time is $t = 2 s$ $t=2s$

Apply the equation

$θ = ω_{0} t + \frac{1}{2} α t^{2}$ $theta=omega_0t+1/2alphat^2$

The angle is

$θ = 2 \cdot 2 + \frac{1}{2} \cdot 3 \cdot 2^{2}$ $theta=2*2+1/2*3*2^2$

$= 4 + 6$ $=4+6$

$= 10 r a d$ $=10rad$