a) What is the acceleration of the blocks? b) What is the net force on each block? c) What is the tension in the string?

A pulley with a string has 58 kg on one end and 95kg at the other.

2 Answers
Mar 12, 2018

see below

Explanation:

From the second dynamic equation
F= ma
and knowing that the total force is the difference of the two forces, while the mass is the sum, you have the aceleration
a= F/m= ((95-58) kg xx 9,8 m/s^2)/((95+58)kg)=2.4 m/s^2=
On the block that is going down there is a net force given by the gravity force less the inerzial force
F= 95 kg xx (9,8-2,4) m/s^2=7.0 xx 10^2 N
On the block that is going up there is a net force given by the inertial force plus the gravity force
F= 58 kg xx (9,8 +2,4) m/s^2=7.0 xx 10^2 N
the tension in the string is the sum
T=14 xx 10^2 N

Mar 12, 2018

a.) acceleration of both the blocks =2.37 ms^-2

b.) net force on 58 Kg is 137.46N acting upwards,and net force on 95 Kg is 225.15N acting downwards.

c.) tension in the string is 705.86 N

Please see images below,

Explanation:

enter image source here