a) What is the acceleration of the blocks? b) What is the net force on each block? c) What is the tension in the string?

A pulley with a string has 58 kg on one end and 95kg at the other.

2 Answers
Andrea B.
Mar 12, 2018

see below

Explanation:

From the second dynamic equation
#F= ma#
and knowing that the total force is the difference of the two forces, while the mass is the sum, you have the aceleration
#a= F/m= ((95-58) kg xx 9,8 m/s^2)/((95+58)kg)=2.4 m/s^2#=
On the block that is going down there is a net force given by the gravity force less the inerzial force
#F= 95 kg xx (9,8-2,4) m/s^2=7.0 xx 10^2 N#
On the block that is going up there is a net force given by the inertial force plus the gravity force
#F= 58 kg xx (9,8 +2,4) m/s^2=7.0 xx 10^2 N#
the tension in the string is the sum
#T=14 xx 10^2 N #

Jane
Mar 12, 2018

#a.) # acceleration of both the blocks =#2.37 ms^-2#

#b.)# net force on #58 Kg# is #137.46N# acting upwards,and net force on #95 Kg# is #225.15N# acting downwards.

#c.)# tension in the string is #705.86 N#

Please see images below,

Explanation:

enter image source here

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