A very large boulder with a volume of #1200# #L# has a mass of #1.4 * 10^9# 3g#. What is the density of the boulder?

1 Answer
anor277
Jan 3, 2016

Density is mass per unit volume, so simply take the ratio.

Explanation:

#(1.4xx10^9*g)/(1200*L)# #=# #??# #g*L^-1#. Note that by setting up the equation this way, and using actual units of mass and volume, I get a final unit that makes sense dimensionally.

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