A triangle has sides A, B, and C. The angle between sides A and B is $\frac{π}{8}$ $pi/8$ . If side C has a length of $1$ $1$ and the angle between sides B and C is $\frac{π}{12}$ $pi/12$ , what is the length of side A?

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Answer 1 · 2016-06-28T17:39:36

$A = 0.68$ $A=0.68$

you can use the Euler theorem:

$\frac{A}{sin ˆ B C} = \frac{C}{sin ˆ A B}$ $A/sin hat (BC)=C/sin hat (AB)$

$A = C \frac{sin ˆ B C}{sin ˆ A B}$ $A= C sin hat(BC)/sin hat (AB)$

$A = 1 \frac{sin (\frac{π}{12})}{sin (\frac{π}{8})}$ $A=1sin(pi/12)/sin(pi/8)$

$A = 0.68$ $A=0.68$

A triangle has sides A, B, and C. The angle between sides A and B is π8pi/8. If side C has a length of 11 and the angle between sides B and C is π12pi/12, what is the length of side A?