A triangle has sides A, B, and C. The angle between sides A and B is pi/8π8. If side C has a length of 6 6 and the angle between sides B and C is pi/12π12, what is the length of side A?

1 Answer
Nov 25, 2017

A=(6sin(pi/12))/sin(pi/8)~=4.06A=6sin(π12)sin(π8)4.06

Explanation:

We can use the the Law of sines, which states that the ratio of the length of a side to the sine of its opposite angle is equal for all sides and angles in a triangle. You can also express this using the following equation:

sin(alpha)/a=sin(beta)/b=sin(gamma)/csin(α)a=sin(β)b=sin(γ)c

where alphaα is the opposite side to aa, betaβ is the opposite side to bb and gammaγ is the opposite side to cc.

If you draw up the triangle, you can see that pi/8π8 is the angle opposite CC and pi/12π12 is the angle opposite AA. Using the Law of sines, we can setup the following equation:

sin(pi/8)/6=sin(pi/12)/Asin(π8)6=sin(π12)A

Asin(pi/8)=6sin(pi/12)Asin(π8)=6sin(π12) (using cross-multiplication)

A=(6sin(pi/12))/sin(pi/8)~=4.06A=6sin(π12)sin(π8)4.06