A triangle has sides A, B, and C. The angle between sides A and B is (pi)/6. If side C has a length of 14 and the angle between sides B and C is (5pi)/12, what are the lengths of sides A and B?

1 Answer
Binayaka C.
May 27, 2016

The length of the sides: A=B=27.05(2dp)

Explanation:

The angle between sides A and B is /_C= pi/6=180/6=30^0
The angle between sides B and C is /_A= (5*pi)/12=5*180/12=75^0
The angle between sides C and A is /_B= 180-(30+75)=75^0
C=14(given). We know A/sinA=B/sinB=C/sinC :. A=C*sinA/sinC
:.A=14*sin75/sin30 =27.05(2dp) Similarly B=C*sinB/sinC :.B=14*sin75/sin30 =27.05(2dp)

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