A triangle has sides A, B, and C. The angle between sides A and B is π6. If side C has a length of 2 and the angle between sides B and C is 5π12, what are the lengths of sides A and B?

1 Answer

side a=6+2=3.863703305
side b=6+2=3.863703305

Explanation:

The given parts of the triangle are
side c=2
Angle A=5π12=75
Angle C=π6=30

The third angle B can be readily solved

A+B+C=180

75+B+30=180

B=180105=75

Therefore we have an isosceles triangle with angles A and B equal.

solve side a using Sine Law

asinA=csinC

a=csinAsinC=2sin75sin30=6+2
by the definition of Isosceles triangle

b=a=6+2

We can check triangle using the Mollweide's Equation which involves all the 6 parts of the triangle

acb=sin(12(AC))cos(12(B))

6+226+2=sin(12(7530))cos(12(75))

0.4823619098=0.4823619098

This means all the 6 parts are correct.

God bless....I hope the explanation is useful.