A triangle has sides A, B, and C. The angle between sides A and B is (pi)/6. If side C has a length of 5 and the angle between sides B and C is ( pi)/2, what are the lengths of sides A and B?

1 Answer

A=10 & B=5\sqrt3

Explanation:

The angle between sides A & C

=\pi-\frac{\pi}{6}-\pi/2

=\pi/3

Now, using Sine rule in the given triangle as follows

\frac{A}{\sin(\pi/2)}=\frac{B}{\sin(\pi/3)}=\frac{C}{\sin(\pi/6)}

\frac{A}{1}=\frac{B}{\sqrt3/2}=\frac{5}{1/2}

A=2/\sqrt3 B=10

\implies A=10 &

B=\sqrt3/2\times 10

=5\sqrt3