A triangle has sides A, B, and C. The angle between sides A and B is (pi)/6. If side C has a length of 2 and the angle between sides B and C is (7pi)/12, what are the lengths of sides A and B?

1 Answer
Mar 28, 2018

color(brown)(a = 3.86, b = 2.828

Explanation:

![http://www.dummies.com/education/math/trigonometry/laws-of-sines-and-cosines/](useruploads.socratic.org)

hat A = (7pi)/12, hat C = pi/6, hat B = pi - (7pi)/12 - pi/6 = pi/4, c = 2

Applying the law of sines,

a / sin A = b / sin B = c / sin C

a = (c * sin A) / sin C = (2 * sin ((7pi)/12))/ sin (pi/6) = 3.86

b = (c * sin B) / sin C = (2 * sin (pi/4)) / sin (pi/6) = 2.828