A triangle has sides A, B, and C. The angle between sides A and B is $(pi)/6$ and the angle between sides B and C is $pi/6$ . If side B has a length of 2, what is the area of the triangle?

Question

1477 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-27T03:53:38

$color(indigo)(Delta " " A_t = (1/2) ab sin C = 0.575 " sq units"$

$hat A = pi/6, hat C = pi/6, b = 2$

To find the area of the isosceles triangle.

$hat B = pi - pi/6 - pi/6 = (2pi)/3$

![http://www.dummies.com/education/math/trigonometry/laws-of-sines-and-cosines/]( useruploads.socratic.org )

$a = (b * sin A) / sin B = (2 * sin (pi/6)) / sin ((2pi)/3) = 1.15 " units"$

$Delta " " A_t = (1/2) ab sin C = (1/2) * 1.15 * 2 * sin (pi/6) = 0.575$

A triangle has sides A, B, and C. The angle between sides A and B is (pi)/6(pi)/6 and the angle between sides B and C is pi/6pi/6. If side B has a length of 2, what is the area of the triangle?