A triangle has sides A, B, and C. The angle between sides A and B is $(pi)/4$ and the angle between sides B and C is $pi/6$ . If side B has a length of 2, what is the area of the triangle?

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Answer 1 · 2017-07-08T15:08:05

The area of the triangle is $=0.74u^2$

The angle between side $A$ and $C$ is

$=pi-(1/4pi+1/6pi)=pi-5/12pi=7/12pi$

Applying the sine rule to the triangle

$A/sin(1/6pi)=B/sin(7/12pi)=2/sin(7/12pi)=2.07$

$A=2.07*sin(1/2pi)=1.04$

The area of the triangle is

$=1/2*A*B*sin(1/4pi)=1/2*1.04*2*sin(1/4pi)=0.74u^2$

A triangle has sides A, B, and C. The angle between sides A and B is (pi)/4(pi)/4 and the angle between sides B and C is pi/6pi/6. If side B has a length of 2, what is the area of the triangle?