Let's write this information in a table, where capital letters correspond to angles , lowercase to lengths :
Acolor(white)(00)pi/12color(white)(00000)acolor(white)(00)A00π1200000a00
Bcolor(white)(00)color(white)(pi/12)color(white)(00000)bcolor(white)(00)B00π1200000b00
Ccolor(white)(00)pi/3color(white)(0)color(white)(00000)c color(white)(00)8C00π3000000c008
All angles in a triangle add up to 180^o180o, or piπ
pi/12+pi/3π12+π3 only equals (5pi)/125π12.
(12pi)/12-(5pi)/12=(7pi)/1212π12−5π12=7π12
That's the remaining angle:
Acolor(white)(00)pi/12color(white)(00000)acolor(white)(00)A00π1200000a00
Bcolor(white)(00)color(black)((7pi)/12)color(white)(00000)bcolor(white)(00)B007π1200000b00
Ccolor(white)(00)pi/3color(white)(0)color(white)(00000)c color(white)(00)8C00π3000000c008
We can use law of sines to find the other lengths:
(sin(pi/3))/8=(sin(pi/12))/asin(π3)8=sin(π12)a
a~~2.391a≈2.391
Just, for fun, let's also find length b
(sin(pi/3))/8=(sin((7pi)/12))/bsin(π3)8=sin(7π12)b
b~~8.923b≈8.923