A triangle has sides A, B, and C. The angle between sides A and B is (pi)/3π3. If side C has a length of 16 16 and the angle between sides B and C is ( 3 pi)/83π8, what are the lengths of sides A and B?

1 Answer
Mar 26, 2018

color(green)("length of side " a) = (c * sin A) / sin C = color(green)(17.07)length of side a=csinAsinC=17.07

color(green)("Length of side " b) = (c * sin B) / sin C = color(green)(2.41)Length of side b=csinBsinC=2.41

Explanation:

"Given : " hat C = pi/3, c = 16, hat A = (3pi) / 8Given : ˆC=π3,c=16,ˆA=3π8

"To find lengths of sides a & b"To find lengths of sides a & b

![http://www.dummies.com/education/math/trigonometry/laws-of-sines-and-cosines/](useruploads.socratic.org)

hat B = pi - pi/3 - (5pi)/8 = pi/24ˆB=ππ35π8=π24

Applying Law of sines,

a / sin A = b / sin B = c / sin CasinA=bsinB=csinC

color(green)(a) = (c * sin A) / sin C = (16 * sin ((3pi)/8)) / sin(pi/3) = color(green)(17.07)a=csinAsinC=16sin(3π8)sin(π3)=17.07

color(green)(b) = (c * sin B) / sin C = (16 * sin (pi/24)) / sin(pi/3) = color(green)(2.41)b=csinBsinC=16sin(π24)sin(π3)=2.41