A triangle has sides A, B, and C. The angle between sides A and B is #pi/3# and the angle between sides B and C is #pi/12#. If side B has a length of 42, what is the area of the triangle?

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Answer 1 · 2016-02-13T15:08:40

Area#=204.669# square units

solve for the height #h# first

#b=h*cot (pi/12)+h*cot (pi/3)#

#42=h(cot (pi/12)+cot (pi/3))#

#h=42/(cot (pi/12)+cot (pi/3))#

#h=9.74613#

Area#=1/2*b*h#

Area#=1/2*42*9.74613#

Area#=204.669#

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