A triangle has sides A, B, and C. The angle between sides A and B is $pi/3$ and the angle between sides B and C is $pi/12$ . If side B has a length of 3, what is the area of the triangle?

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Answer 1 · 2017-07-10T06:21:04

The area is $=1.04u^2$

The third angle of the triangle is

$=pi-(pi/3+pi/12)=pi-5/12pi=7/12pi$

We apply the sine rule to the triangle

$A/sin(1/12pi)=B/sin(7/12pi)$

$A/sin(1/12pi)=3/sin(7/12pi)=3.11$

$A=3.11*sin(1/12pi)=0.8$

The area of the triangle is

$=1/2ABsin(1/3pi)=0.5*0.8*3*sin(1/3pi)=1.04$

A triangle has sides A, B, and C. The angle between sides A and B is pi/3pi/3 and the angle between sides B and C is pi/12pi/12. If side B has a length of 3, what is the area of the triangle?