A triangle has sides A, B, and C. The angle between sides A and B is $(pi)/2$ . If side C has a length of $25$ and the angle between sides B and C is $pi/12$ , what is the length of side A?

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A triangle has sides A, B, and C. The angle between sides A and B is $(pi)/2$ . If side C has a length of $25$ and the angle between sides B and C is $pi/12$ , what is the length of side A?

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Answer 1 · 2017-10-08T17:54:02

Length of side A = 6.4705

Explanation:

$C/sinC=A/sinA$
Given side $C=25$ , $/_C=(pi/2)$ & $/_A=(pi/12)$
$:.25/sin(pi/2)=A/sin(pi/12)$
$A=(25*sin(pi/12))/sin(pi//2)$
$A=(25*sin(pi/12))/1=25*0.2588=$ 6.4705

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A triangle has sides A, B, and C. The angle between sides A and B is $(pi)/2$ . If side C has a length of $25$ and the angle between sides B and C is $pi/12$ , what is the length of side A?

1 Answer

Explanation:

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Explanation:

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