A triangle has sides A, B, and C. The angle between sides A and B is (pi)/2 and the angle between sides B and C is pi/12. If side B has a length of 9, what is the area of the triangle?

1 Answer
Deepak G.
Aug 12, 2016

=10.85

Explanation:

Clearly this is a right-angled triangle where base= B=9 and angle between A and C =pi-(pi/2+pi/12)=pi-((7pi)/12)=(5pi)/12
Therefore we can write
B/A=tan((5pi)/12)
or
9/A=3.73
or
A=9/3.73
or
A=2.41 (Pl.note A is the height)
Area of the triangle =1/2times height timesbase=1/2times2.41times9=10.85

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