A triangle has sides A, B, and C. The angle between sides A and B is $pi/12$ and the angle between sides B and C is $pi/12$ . If side B has a length of 5, what is the area of the triangle?

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Answer 1 · 2017-01-19T08:42:06

$=1.675 unit^2$

The other angle is $pi-pi/12-pi/12=10/12pi = 5/6pi$

Since it is an isosceles triangle with 2 equal size of sides,
The height of triangle, $h =5/2tan(pi/12)$
$h =5/2tan(pi/12)$

The area or triangle $=1/2*5*h$
$=1/2*5*5/2tan(pi/12)$

$=25/4*0.268$

$=1.675 unit^2$

A triangle has sides A, B, and C. The angle between sides A and B is pi/12pi/12 and the angle between sides B and C is pi/12pi/12. If side B has a length of 5, what is the area of the triangle?