A triangle has sides A, B, and C. The angle between sides A and B is $(7pi)/12$ . If side C has a length of $16$ and the angle between sides B and C is $pi/12$ , what is the length of side A?

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Answer 1 · 2017-11-30T21:59:15

$4.29$

sine rule: $a/sin A = b/sin B = c/sin C$

$c$ / $sin$ (angle between A and B) = $a$ / $sin$ (angle between B and C)

$16/sin((7pi)/12) = a/sin(pi/12)$

multiply both sides by $sin (pi/12):$

$a = (16sin(pi/12)) /sin((7pi)/12)$

$= 4.29$ ( $3$ s.f.)

A triangle has sides A, B, and C. The angle between sides A and B is (7pi)/12(7pi)/12. If side C has a length of 16 16 and the angle between sides B and C is pi/12pi/12, what is the length of side A?