A triangle has sides A, B, and C. The angle between sides A and B is #(7pi)/12# and the angle between sides B and C is #pi/12#. If side B has a length of 3, what is the area of the triangle?

1 Answer
Binayaka C.
May 28, 2016

The area of the triangle is #1.30# #units^2#

Explanation:

The angle between sides A and B is #/_C=7*180/12=105^0#
The angle between sides B and C is #/_A=180/12=15^0#
The angle between sides C and A is #/_B=180-(105+15)=60^0#
B=3 (given) We know #B/sinB=C/sinC or C =3*sin105/sin60=3.35#
Now #B=3 ;C=3.35# and their included angle#/_A=15^0# so Area #=1/2 B*C*sinA =(3*3.35)/2*sin15=1.30(2dp) units^2#[Ans]

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