A triangle has sides A, B, and C. The angle between sides A and B is $(5pi)/6$ . If side C has a length of $1$ and the angle between sides B and C is $pi/12$ , what are the lengths of sides A and B?

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Answer 1 · 2016-06-13T15:23:56

side $a=0.517638" "$ unit

side $b=0.517638" "$ unit

The triangle is isosceles with angles $A=B$ and therefore sides $a=b$

with angle $C=(5pi)/6$ and angle $A=B=pi/12$

also side $c=1$

Using Sine Law

$a/sin A=b/sin B=c/sin C$

Solve side $a$

$a=c*sin A/sin C=1*sin (pi/12)/sin ((5pi)/6)=0.517638$

it follows

$b=a=0.517638$

God bless...I hope the explanation is useful.

A triangle has sides A, B, and C. The angle between sides A and B is (5pi)/6(5pi)/6. If side C has a length of 1 1 and the angle between sides B and C is pi/12pi/12, what are the lengths of sides A and B?