A triangle has sides A, B, and C. The angle between sides A and B is $(5pi)/6$ and the angle between sides B and C is $pi/12$ . If side B has a length of 6, what is the area of the triangle?

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Answer 1 · 2018-02-17T12:12:47

Area $A_t =/(1/2) 6 * 6 * sin ((5pi)/6) = color(red)(9$

$hatA = pi/12, hatC = (5pi)/6, b = 6$

$hatB = pi - (5pi)/6 - pi/12 = pi/12$

$hatA = hatB, :. a = b = 6$ (isosceles triangle)

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Area $A_t =/(1/2) 6 * 6 * sin ((5pi)/6) = color(red)(9$

A triangle has sides A, B, and C. The angle between sides A and B is (5pi)/6(5pi)/6 and the angle between sides B and C is pi/12pi/12. If side B has a length of 6, what is the area of the triangle?