A triangle has sides A, B, and C. The angle between sides A and B is $(5pi)/6$ and the angle between sides B and C is $pi/12$ . If side B has a length of 19, what is the area of the triangle?

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Answer 1 · 2018-06-10T02:06:23

$color(green)("Area of " Delta = 90.25 " sq units"$

$hat A = pi/12, hat C (5pi)/6, b = 19, hat B = pi/12$

Given triangle is isosceles and sides b & a are equal as both the angles are equal.

$a = b = 19$

$"Area of the " Delta = (1/2) a b sin C = (1/2) * 19^2 * sin ((5pi)/6)$

$color(green)("Area of " Delta = 90.25 " sq units"$

A triangle has sides A, B, and C. The angle between sides A and B is (5pi)/6(5pi)/6 and the angle between sides B and C is pi/12pi/12. If side B has a length of 19, what is the area of the triangle?