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A triangle has sides A, B, and C. The angle between sides A and B is #(5pi)/6# and the angle between sides B and C is #pi/12#. If side B has a length of 19, what is the area of the triangle?

1 Answer

sankarankalyanam

Jun 10, 2018

#color(green)("Area of " Delta = 90.25 " sq units"#

Explanation:

#hat A = pi/12, hat C (5pi)/6, b = 19, hat B = pi/12#

Given triangle is isosceles and sides b & a are equal as both the angles are equal.

#a = b = 19#

#"Area of the " Delta = (1/2) a b sin C = (1/2) * 19^2 * sin ((5pi)/6)#

#color(green)("Area of " Delta = 90.25 " sq units"#

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