A triangle has sides A, B, and C. The angle between sides A and B is $(5pi)/12$ and the angle between sides B and C is $pi/12$ . If side B has a length of 11, what is the area of the triangle?

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Answer 1 · 2018-06-17T13:11:53

The area is given by $A=121/2*((1+sqrt(3))/(2*sqrt(2)))^2$

The third angle is
$pi/2$
So we have
$A=1/2ac$
and from

$sin(pi/12)=a/11$
$sin(5*pi/12)=c/11$
and
$sin(pi/12)=sin(5pi/12)=(1+sqrt(3))/(2*sqrt(2))$

A triangle has sides A, B, and C. The angle between sides A and B is (5pi)/12(5pi)/12 and the angle between sides B and C is pi/12pi/12. If side B has a length of 11, what is the area of the triangle?