A triangle has sides A, B, and C. The angle between sides A and B is (5pi)/12 and the angle between sides B and C is pi/12. If side B has a length of 10, what is the area of the triangle?

1 Answer
Binayaka C.
May 4, 2016

Hence Area of the right angled triangle is 12.5 square units.

Explanation:

The angle between sides A and B is /_C=5*180/12=75^0
The angle between sides B and C is /_A=180/12=15^0 :. /_B=180-(75+15)=90^0 Side B = 10 Applying sine law A/sinA=B/sinB=C/sinC
we get A= 10*sin15=2.588 and C= 10*sin75=9.659 Hence Area of the right angled triangle is = 1/2*9.659*2.588=12.5 Square units.
Here, Base = 9.659 and Height =2.588[Ans]

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