A triangle has sides A, B, and C. The angle between sides A and B is $(5pi)/12$ and the angle between sides B and C is $pi/12$ . If side B has a length of 15, what is the area of the triangle?

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A triangle has sides A, B, and C. The angle between sides A and B is $(5pi)/12$ and the angle between sides B and C is $pi/12$ . If side B has a length of 15, what is the area of the triangle?

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Answer 1 · 2016-08-11T20:40:31

$=28.13$

Explanation:

The angle between $A$ and $C$ $=pi-((5pi)/12+pi/12)=pi-pi/2=pi/2$
This shows that triangle is right-angled with hypotenuse $=B=15$
Hence $height=$ side $A=15sin(pi/12)$ and $base=$ side $B=15cos(pi/12)$
Therefore Area of the triangle $=1/2times height times base$
$=1/2times15sin(pi/12)15cos(pi/12)$
$=225/2(0.2588)(0.966)$
$=28.13$

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A triangle has sides A, B, and C. The angle between sides A and B is $(5pi)/12$ and the angle between sides B and C is $pi/12$ . If side B has a length of 15, what is the area of the triangle?

1 Answer

Explanation:

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A triangle has sides A, B, and C. The angle between sides A and B is (5pi)/12(5pi)/12 and the angle between sides B and C is pi/12pi/12. If side B has a length of 15, what is the area of the triangle?

1 Answer

Explanation:

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A triangle has sides A, B, and C. The angle between sides A and B is $(5pi)/12$ and the angle between sides B and C is $pi/12$ . If side B has a length of 15, what is the area of the triangle?