A triangle has sides A, B, and C. The angle between sides A and B is $(5pi)/12$ and the angle between sides B and C is $pi/12$ . If side B has a length of 12, what is the area of the triangle?

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Answer 1 · 2017-02-02T03:55:27

Area = 18 units

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The given triangle is sketched as in the figure above. Angle B would be $pi -pi/12 -(5pi)/12 = pi/2$

Side b is 12. It is the hypotenuse because it is opposite the right angle B.

For area, base and altitude is required. In this case it is side 'a' and side 'c'.

Side 'c' = $12 cos (pi/12)$

Side 'a' = $12 sin (pi/12)$

Area = $1/2 (12 sin (pi/12) *12 cos (pi/12))$
= $72 sin (pi/12) cos (pi/12)$ = $36 (2sin (pi/12) cos (pi/12))$ = 36 sin pi/6= 36 $1/2$ = 18

Area = 18 units.

A triangle has sides A, B, and C. The angle between sides A and B is (5pi)/12(5pi)/12 and the angle between sides B and C is pi/12pi/12. If side B has a length of 12, what is the area of the triangle?